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September 1, 2014

September 1, 2014

Posted by **Taylor** on Wednesday, February 17, 2010 at 4:46pm.

- Trig -
**Reiny**, Wednesday, February 17, 2010 at 8:23pmsin 4x

= 2sin(2x)cos(2x)

= 2(2sinxcosx)(1 - 2sin^2 x)

= 4sinxcosx(1 - 2sin^2 x)

this is expressed in terms of trig functions of x.

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