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Posted by on Wednesday, February 17, 2010 at 4:46pm.

How do you express sin4x as a trigonometric funcition of x using the identities? I think that you are supposed to start with the sine sum identity and then use the double angle identities for sin2A and cos2A, but after that I get stuck...

  • Trig - , Wednesday, February 17, 2010 at 8:23pm

    sin 4x
    = 2sin(2x)cos(2x)
    = 2(2sinxcosx)(1 - 2sin^2 x)
    = 4sinxcosx(1 - 2sin^2 x)

    this is expressed in terms of trig functions of x.

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