8x+5y=184, x-y=3

Ren this is substitution method and I am so confused

ok here is what i got:

8x+5y=184 (1)
x-y=3 (2)

from equation (1) 8x+5y=184 => 8x=184-5y
x=184-5y/8 call this equation (3)

substitute equation (3) in equation (2)

184-5y/8-y =3
(184/8)-(5y/8)-y=3
(184/8)-(13y/8)=3
(184/8)-3=13y/8
160/8=13y/8
20=13y/8
[cross multiply]
20(8)=13y
160=13y
160/13=y

for y=160/13, substitute in equation (3)

x=184-(5(160/13))/8
x=(184-800/13)/8
x=(1592/13)/8
x=(1592/13) * (1/8)
x=199/13

x=199/13 , y=160/13

If you plug back in these values for x and y in equations 1 and 2, you are suppose to get back the answers there are equal to....

To solve the system of equations:

1. 8x + 5y = 184
2. x - y = 3

There are several methods to solve a system of equations, such as substitution, elimination, or graphing. Let's use the elimination method to solve this particular system.

Step 1: Multiply both sides of Equation 2 by 8 to make the coefficients of 'x' in both equations the same.

Equation 1: 8x + 5y = 184
Equation 2: 8x - 8y = 24

Step 2: Now, subtract Equation 2 from Equation 1 to eliminate the 'x' variable.

(8x + 5y) - (8x - 8y) = 184 - 24
8x + 5y - 8x + 8y = 160
13y = 160
y = 160 / 13

Step 3: Substitute the value of 'y' back into Equation 2 to find the value of 'x'.

x - (160 / 13) = 3
13x - 160 = 39
13x = 39 + 160
13x = 199
x = 199 / 13

Therefore, the solution to the system of equations is x = 199/13 and y = 160/13.