lim sinx
as x approaches pie/r
A) -(2^1/2)/2
B) (2^1/2)/2
C) (2^-1/2)/4
D) DOES NOT EXIST
E) -(2^(-1/2))/4
I do not understand. I am going to lunch. Will check when I get back but another teacher will probably see it.
as x approaches 3.141593/4
4 not r, fingers are not cooperating
sin x as x--> pi/4
Do not need a limit as far as I know
45, 45, 90 triangle 1,1,sqrt2
sin pi/4 = 1/sqrt 2 = sqrt 2/2 = 2^(1/2)/2
which is B
To find the limit of sin(x) as x approaches π/√2, we can directly substitute π/√2 into the function and evaluate it.
lim sin(x) = sin(π/√2)
Next, we need to calculate the value of sin(π/√2). However, the exact value of sin(π/√2) is not a standard value, so we need to use a scientific calculator or a mathematical software to find an approximate value.
Using a calculator, we find sin(π/√2) ≈ 0.3632.
Now, we compare this value to the given options:
A) -(2^1/2)/2 ≈ -0.7071
B) (2^1/2)/2 ≈ 0.7071
C) (2^-1/2)/4 ≈ 0.1768
D) DOES NOT EXIST
E) -(2^(-1/2))/4 ≈ -0.1768
Looking at the options, we see that none of the given options exactly match the value of sin(π/√2) that we calculated. Therefore, the correct answer is D) DOES NOT EXIST.