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calculus

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write equation of line that passes through the point
1)parallel to the given line
2)perpendicular to the given line

pt (6,2)
line -9x+9y=144

a)para -9x+9y=-72
perp -9x-9y=-36

b)para -9x-9y=-36
perp -9x-9y=-72

c)para 9x+9y=-36
perp 9x-9y=-72

d)para -9x-9y=-72
perp -9x-9y=-72

  • calculus - ,

    Write equations in the form

    y = m x + b

    then m is the slope

    then put the coordinates in to get b

    in this case
    9 y = 9 x + 144
    or
    y = 1 x + 16
    slope is 1 so parallel is
    y = x + b
    through (6,2)
    2 = 6 + b
    b = -4
    so for parallel y = x - 4
    or
    9 y = 9 x - 36
    9x - 9y = 36
    So I get none of the above for the parallel line. Typo?

  • calculus - ,

    sorry I can't seem to type this morning

    b) para -9x+9y=-36
    perp -9x-9y=-72

  • calculus - ,

    ok for parallel

    now perp
    y = -x +b
    (6,2)
    2 = -6+b
    b = 8
    so
    y = -1x + 8
    9y = -9x + 72
    -9x - 9y = -72 yes

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