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March 30, 2015

March 30, 2015

Posted by **ashley** on Wednesday, February 17, 2010 at 10:38am.

1)parallel to the given line

2)perpendicular to the given line

pt (6,2)

line -9x+9y=144

a)para -9x+9y=-72

perp -9x-9y=-36

b)para -9x-9y=-36

perp -9x-9y=-72

c)para 9x+9y=-36

perp 9x-9y=-72

d)para -9x-9y=-72

perp -9x-9y=-72

- calculus -
**Damon**, Wednesday, February 17, 2010 at 10:53amWrite equations in the form

y = m x + b

then m is the slope

then put the coordinates in to get b

in this case

9 y = 9 x + 144

or

y = 1 x + 16

slope is 1 so parallel is

y = x + b

through (6,2)

2 = 6 + b

b = -4

so for parallel y = x - 4

or

9 y = 9 x - 36

9x - 9y = 36

So I get none of the above for the parallel line. Typo?

- calculus -
**ashley**, Wednesday, February 17, 2010 at 11:07amsorry I can't seem to type this morning

b) para -9x+9y=-36

perp -9x-9y=-72

- calculus -
**Damon**, Wednesday, February 17, 2010 at 11:13amok for parallel

now perp

y = -x +b

(6,2)

2 = -6+b

b = 8

so

y = -1x + 8

9y = -9x + 72

-9x - 9y = -72 yes

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