Posted by Tony on Wednesday, February 17, 2010 at 1:04am.
2) YOur balanced equation gives the answer: 1 mole of calcium carbonate yields one mole of carbon dioxide, which is 12 grams carbon. So for .55grams, you must have had .55/12 moles of calcium carbonate.
3. knowing the moles of calcium carbonate, change it to mass (grams).
What is the molarity of a solution containing 8 grams of solute in 500 mL of solution? Round to the nearest hundredth. Don't forget the units! (gram formula mass of solute = 24 g)
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