Two aqueous solutions of sucrose, C12H22O12, are mixed. One solution is 0.1495 M sucrose and has d = 1.018 g/mL; the other is 12.00 sucrose by mass and has d = 1.038 g/ml.
Calculate the moles C12H22O12 percent in the mixed solution.
Please provide steps
To calculate the moles of sucrose (C12H22O12) percent in the mixed solution, you'll need to follow these steps:
Step 1: Find the mass of the first solution.
Mass of the first solution = volume of the solution x density of the solution
Volume of the solution = Molarity (M) x volume (in liters)
Since the Molarity is given as 0.1495 M, you need to convert it to moles per liter (mol/L) to be consistent with the volume units.
Moles per liter = 0.1495 moles / 1 L
Once you have the volume in liters, multiply it by 1000 to convert it to milliliters (mL).
Volume in mL = (Moles per liter) x (volume in L) x 1000
Then, calculate the mass using the given density.
Mass of the first solution = Volume in mL x density of the solution
Mass of the first solution = volume in mL x 1.018 g/mL
Step 2: Find the mass of the second solution.
Since the composition of the second solution is given as 12.00 sucrose by mass, it means there are 12.00 grams of sucrose in 100 grams of the solution.
Therefore, the mass of the second solution = 12.00 g
Step 3: Find the total mass of the mixed solution.
Total mass of the mixed solution = mass of the first solution + mass of the second solution
Step 4: Calculate the moles of C12H22O12 in the mixed solution.
To calculate the moles, you'll need to first calculate the total mass of sucrose (C12H22O12) in the solution by adding the moles present in each solution.
Moles of C12H22O12 in the first solution = Mass of the first solution / Molar mass of sucrose
Moles of C12H22O12 in the second solution = Mass of the second solution / Molar mass of sucrose
Total moles of C12H22O12 in the mixed solution = Moles of C12H22O12 in the first solution + Moles of C12H22O12 in the second solution
Step 5: Calculate the moles percent of C12H22O12 in the mixed solution.
Moles percent of C12H22O12 = (Total moles of C12H22O12 / Total moles of all components) x 100
Please note that to perform the calculations, you will need the molar mass of sucrose, which is approximately 342.30 g/mol. By following these steps, you should be able to calculate the moles of sucrose percent in the mixed solution.