Posted by **PLEASE HELP ME** on Tuesday, February 16, 2010 at 11:31pm.

A radio tower 500 feet high is located on the side of a hill with an inclination to the horizontal of 5 degrees. How long should two guy wires be if they are to connect to the top of the tower and be secured at two points 100 feet directly above and directly below the base of the tower?

- MATH -
**bobpursley**, Tuesday, February 16, 2010 at 11:45pm
What do you mean directly below the base of the tower? That is underground.

- MATH -
**PATEL**, Thursday, November 29, 2012 at 11:28pm
Using the law of cosines:

x1^2 = 100^2 + 500^2 - 2*100*500*cos(85)

x1^2 = 100^2 + 500^2 - 2*100*500*0.087155743

x1^2 = 251284.4257

x1 = 501.28

Similarly, for the other side, we know that

the angle between the tower and the ground

is 90+5=95. Using the law of cosines to

solve for the length of the second guy wire:

x2^2 = 100^2 + 500^2 - 2*100*500*cos(95)

x2^2 = 100^2 + 500^2 - 2*100*500*(-0.087155743)

x2^2 = 268715.5743

x2 = 518.38

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