Posted by engmath on .
The vector position of a 3.65 g particle moving in the xy plane varies in time according to the following equation.
r1 = <(3i+3j)t + 2jt^2>
At the same time, the vector position of a 5.60 g particle varies according to the following equation.
r2 = <3i - 2it^2 - 6jt>
For each equation, t is in s and r is in cm. Solve the following when t = 2.90
(a) Find the vector position of the center of mass.
(b) Find the linear momentum of the system.
(c) Find the velocity of the center of mass.
(d) Find the acceleration of the center of mass.
(e) Find the net force exerted on the two-particle system.
Maybe someone could just explain to me how to solve for each part because I'm thoroughly confused. THANK YOU.