Posted by **angel** on Tuesday, February 16, 2010 at 7:36pm.

Consider the solid obtained by rotating the region bounded by the given curves about the line x = -3.

y = x^2 , x = y^2

Find the volume V of this solid.

I keep finding the wrong answer.

- calculus 2 -
**Damon**, Tuesday, February 16, 2010 at 7:59pm
The two parabolas enclose an area between (0,0) and (1,1)

y = x^2 or x=sqrt y is on the right and lower there.

y = x^(1/2) or x = y^2 is above and left there. (All in quadrant one, no worry about signs )

the radius to x = -3 is (3+x)

so outer radius = 3 + sqrt y

inner radius = 3 + y^2

find outer volume

pi (3+y^.5)^2 dy from 0 to 1

find inner volume

pi (3+y^2)^2 dy from 0 to 1

subtract

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