A 893 g sample of a solution of the solute (CH3)2CO in the solvent C4H8O that has a concentration of 28.6 pph(parts per hundred) by mass (CH3)2CO is available. Calculate the amount (g) of acetone that is present in the sample.

Molar Mass (g/mol)
(CH3)2CO 58.05
C4H8O 72.12

Density (kg/m3):
(CH3)2CO 789.9
C4H8O 889.2

Name/Formula:
acetone
(CH3)2CO
tetrahydrofuran
C4H8O

Would that be 893 x 0.286 = ??

To calculate the amount of acetone (CH3)2CO present in the sample, we can use the given concentration of 28.6 pph (parts per hundred) by mass. Here's how you can do the calculations:

Step 1: Convert the given sample mass to kilograms.
The sample mass is 893 grams. To convert it to kilograms, divide by 1000:
893 g รท 1000 = 0.893 kg

Step 2: Calculate the mass of acetone in the sample.
The concentration is given as pph (parts per hundred) by mass, which means that for every 100 parts of the solution, 28.6 parts are acetone.

Since the total mass is 0.893 kg, we can calculate the mass of acetone using the percentage:
Mass of acetone = 28.6/100 * 0.893 kg

Step 3: Convert the mass of acetone to grams.
Multiply the mass in kilograms by 1000 to convert it to grams:
Mass of acetone = (28.6/100 * 0.893 kg) * 1000 g/kg

Step 4: Calculate the amount of acetone in grams.
The molar mass of acetone is given as 58.05 g/mol, which means that 1 mole of acetone has a mass of 58.05 grams.

Now, divide the mass of acetone in grams by the molar mass of acetone to find the amount of acetone in moles:
Amount of acetone (moles) = Mass of acetone (g) / Molar mass of acetone (g/mol)

Finally, multiply the amount in moles by the molar mass of acetone to find the amount of acetone in grams:
Amount of acetone (g) = Amount of acetone (moles) * Molar mass of acetone (g/mol)

Just plug in the values and calculate!

Note: The density values and the formula for tetrahydrofuran (THF, C4H8O) are not required for this calculation.