Posted by Abby on .
In a game of basketball, a forward makes a bounce pass to the center. The ball is thrown with an initial speed of 3.9 m/s at an angle of 25 degrees above the horizontal. It is released 0.75 m above the floor.
What horizontal distance does the ball cover before bouncing?

Physics 
bobpursley,
Break up the initial velocity in to horizontal and vertical components.
vertical
Vi=3.9sin25
hf=ho+vi*t4.9t^2
0=.75+3.9sin25*t4.9t^2 solve for time in air, t.
Then
Horizontal
distance=3.9cos25*t