What is the force between two charged spheres 1.25 cm apart if the charge on one sphere is 2.50 C and the charge on other sphere is 1.75 X 10^-8 C
Is there some failure of Coulomb's law here?
F=kQQ/r^2
The two Q's in the Coulomb equation are different in this case.
Call them
Q1 = 2.50 C and
Q2 = 1.75 * 10^-8 C .
I think you may have left out an exponent on Q1. 2.5 C is enough for a major lightning strike.
You may need to convert r to meters, depending upon which units
you use for k.
how long did it take 4 u 2 knw physics
r is equal 1.25cm
A charge of 4.10 is placed at each corner of a square 0.100 on a side.
Determine the magnitude of the force on each charge.
Determine the direction of the force on each charge. Assume that the positive x-axis is directed to the right.
To calculate the force between two charged spheres, we can use Coulomb's Law. Coulomb's Law states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
The formula for Coulomb's Law is:
F = k * (|q1| * |q2|) / r^2
Where:
F is the force between the charges,
k is the electrostatic constant (9 × 10^9 N m^2/C^2),
|q1| and |q2| are the magnitudes of the charges,
and r is the distance between the charges.
In this case, we have:
|q1| = 2.50 C
|q2| = 1.75 × 10^-8 C
r = 1.25 cm = 0.0125 m
Now, plugging the values we have into the formula, we get:
F = (9 × 10^9 N m^2/C^2) * (|2.50 C| * |1.75 × 10^-8 C|) / (0.0125 m)^2
Simplifying, we have:
F = (9 × 10^9 N m^2/C^2) * (2.50 * 1.75 × 10^-8 C) / (0.0125 m)^2
F = (9 × 10^9 N m^2/C^2) * (4.375 × 10^-8 C^2) / 0.00015625 m^2
F = (39.375 × 10) / 0.00015625 N
F = 2.52 × 10^11 N
Therefore, the force between the two charged spheres is approximately 2.52 × 10^11 Newtons (N).