A rectangle has an area given by A=x^2+7x+2. Find expressions for the possible length and width of the rectangle.
Well, Area >0
A>0 so x^2+7x+2 >0
(x+6.7)(x+.3)>0
so a possible length is x+6.7 and a possible width is x+.3, and x can be any number >.3 ( as long as width is >0)
check my thinking.