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September 30, 2014

September 30, 2014

Posted by **Kristen** on Tuesday, February 16, 2010 at 10:41am.

- Algebra -
**bobpursley**, Tuesday, February 16, 2010 at 11:01amWell, Area >0

A>0 so x^2+7x+2 >0

(x+6.7)(x+.3)>0

so a possible length is x+6.7 and a possible width is x+.3, and x can be any number >.3 ( as long as width is >0)

check my thinking.

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