Calculate the inlet and outlet velociies V1 and V2 using the contiuity equation
V * A = 3000 liters/min = 3*10^6 cm^3/min
A1 = pi*(15)^2 = 706.9 cm^2
A2 = pi*(10)^2 = 314.2 cm^2
V1 = 3*10^6/706.9
= 4244 cm/s = 42.44 m/s
V2 = 95.48 m/s
The steady state energy equation says that
Mdot*(U + P*v + KE + PE)out = Mdot*(U + P*v+ KE+ PE)in + (Power)in
Mdot is the mass flow rate
U is the internal energy, which does not change because inlet and outlet temperatures are equal. KE(per mass) = V^2/2. PE is potential energy which does not change since the inlet and outlet are at the same elevation. P v
is pressure times specific volume, which is the same as pressure divided by density.
The energy equation simplifies to:
Power in = Mdot*[P/density + V^2/2]out -Mdot*[P/density + V^2/2]in
For water, density = constant = 1000 kg/m^3
Mdot = 3 m^3/min * 1000 kg/m^3 = 3000 kg/min = 50 kg/s
First let us calculate the power needed to increase the pressure.
= 50 kg/s*(202*10^5 N/m^2)/1000 kg/m^3
= 60.6*10^6 J/s = 1.01 Megawatts
You need to add to that the additional power needed to increase the kinetic energy
Mdot*[V2^2/2 - V1^2/2]
Take it from there and check my numbers.
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