A car slows from 22 m/s to 3 m/s with an acceleration of -2.1m/s2. How long does this take?

average acceleration a = change in velocity/change in time

-2.1 = (3-22)/t
-2.1 = -19/t
t = 19/2.1

A race car traveling at +44m/s is accelerated to a velocity of +22 m/s over an 11 s interval. What is the displacement during this time?

average speed = 33 m/s

33 * 11 meters

To find the time it takes for the car to slow down from 22 m/s to 3 m/s with an acceleration of -2.1 m/s^2, we can use the formula:

v = u + at

Where:
v = final velocity
u = initial velocity
a = acceleration
t = time

Given that the initial velocity (u) is 22 m/s, the final velocity (v) is 3 m/s, and the acceleration (a) is -2.1 m/s^2, we can rearrange the formula to solve for time:

t = (v - u) / a

Substituting the values into the equation, we have:

t = (3 - 22) / -2.1

t = -19 / -2.1

t ≈ 9.05 seconds

Therefore, it takes approximately 9.05 seconds for the car to slow down from 22 m/s to 3 m/s with an acceleration of -2.1 m/s^2.