Jenna and Tony need quarters for bus fare. Jenna has 3 x as many as Tony.
Together they have $11.00 in quarters. How many coins does each have?
J=3T
J*.25+T*.25=11.00
(3T+T)*.25=11.00
solve for T first.
Always start with "Let" statements.
Let "J" represent the number of quarters Jenna has.
Let "T" represent the number of quarters Tony has.
Using these variables, phrase your question into algebraic equations.
Jenna has 3 x as many as Tony
J = 3T
Together they have $11.00 in quarters. That's 4 quarters in every dollar, so $11 is 44 quarters.
J + T = 44
Now using those two equations, you can substitute and solve.
I leave that to you :)
To find out how many quarters each Jenna and Tony have, we can set up a system of equations based on the information given in the problem.
Let's assume that Tony has x quarters.
According to the problem, Jenna has 3 times as many quarters as Tony. So, Jenna has 3x quarters.
We know that the value of a quarter is $0.25. So, we can write the equations as follows:
x + 3x = 11 (equation 1, representing the total value of quarters)
Simplifying the equation:
4x = 11
Now we can solve for x by dividing both sides of the equation by 4:
x = 11 / 4
x = 2.75
Since we cannot have a fraction of a quarter, we can conclude that Tony has 3 quarters (since the question specifies they need quarters for bus fare, we can assume no other coins are involved).
To find Jenna's number of quarters, we can substitute the value of x into the expression 3x:
3 * 2.75 = 8.25
Therefore, Jenna has 8 quarters.
In summary, Tony has 3 quarters and Jenna has 8 quarters.