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July 6, 2015

Homework Help: Physics

Posted by mike on Monday, February 15, 2010 at 7:26pm.

Question: The amount of internal energy needed to raise the temperature of .25 kg of water by 0.2 degrees Celsius is 209.3 J. How fast must a 0.25 kg baseball travel in order for its kinetic energy to equal this internal energy?

KE = (.5)(m)(v^2)
209.3 J = (.5)(.25kg)(v^2)
1674.4 = v^2 **square root both sides**
v = 40.92

^Is ANY of that correct? If not, can anyone help? Thanks so much

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