posted by blasting on .
When 0.949 g of CaO is added to 200.0 mL of 0.500 M HCl(aq), a temperature increase of 389C is observed.
Assume the solution's final volume is 200.0 mL, the density is 1.00 g/mL, and the heat capacity is 4.184 J/gC.
what is molar heat of reaction, Hrxn, for the reaction of
CaO(s) + 2H+(aq) = Ca2+(aq) + H2O(l) in kj/mol
Can this be right? Water boils at 100 C so how can the temperature increase by 389 degrees? That would have boiled all of the water away.
mass water x specific heat water x delta T = q
That will be q/0.949 g CaO. Convert that to moles CaO.
this is what i did: q=200x389x4.184
then q/0.949g x56.08g/1mol
but i still got the wrong answer
q/ (0.949 g / 56.08 gmol^-1)