consider the reaction in which 410 grams of Ca(NO3)2 react with just the right amount of lithium metal in a single replacement reaction.

1-how many grams of lithium are required?
2- how many grams of each product can be produced?

34.672..for you all you da vinci kids that need help

stuck at step 5! help please!

To find the number of grams of lithium required and the grams of each product produced in the given reaction, we need to use stoichiometry.

1. To determine the grams of lithium required, we first need to write and balance the chemical equation for the reaction.

Ca(NO3)2 + 2Li → 2LiNO3 + Ca

From the balanced equation, we can see that it takes 2 moles of lithium (2Li) to react with 1 mole of Ca(NO3)2. Now we need to convert the given amount of Ca(NO3)2 from grams to moles, and then use the mole ratio to find the grams of lithium required.

To calculate the moles of Ca(NO3)2:
Molar mass of Ca(NO3)2 = (40.08 g/mol × 1) + (14.01 g/mol × 2) + (16.00 g/mol × 6) = 164.09 g/mol
Moles of Ca(NO3)2 = 410 g / 164.09 g/mol ≈ 2.5 mol

Using the mole ratio (from the balanced equation), we can determine the moles of lithium required:
2 moles of Li / 1 mole of Ca(NO3)2 × 2.5 mol of Ca(NO3)2 = 5 moles of Li

Finally, we can calculate the grams of lithium required:
Mass of lithium = 5 moles × molar mass of Li
Molar mass of Li = 6.94 g/mol
Mass of lithium = 5 × 6.94 g ≈ 34.7 grams

Therefore, approximately 34.7 grams of lithium are required for the reaction.

2. To find the grams of each product produced, we need to use the stoichiometry of the balanced equation.

From the balanced equation, we can see that the mole ratio between Ca(NO3)2 and LiNO3 is 1:2.
So, the moles of LiNO3 produced will be twice the moles of Ca(NO3)2 used.

Moles of Ca(NO3)2 = 2.5 mol (calculated earlier)
Moles of LiNO3 produced = 2 × 2.5 mol = 5 mol

Now we can calculate the mass of LiNO3 produced using its molar mass:
Molar mass of LiNO3 = (6.94 g/mol × 1) + (14.01 g/mol × 1) + (16.00 g/mol × 3) = 85.04 g/mol
Mass of LiNO3 produced = 5 mol × 85.04 g/mol = 425.2 grams

Finally, we can calculate the mass of calcium produced using its molar mass:
Molar mass of Ca = 40.08 g/mol
Mass of Ca produced = 2.5 mol × 40.08 g/mol = 100.2 grams

Therefore, approximately 425.2 grams of LiNO3 and 100.2 grams of calcium are produced in the reaction.

2Li + Ca(NO3)2 ==> 2LiNO3 + Ca

Step 2. Convert 410 g Ca(NO3)2 to moles. moles = grams/molar mass.

3. Using the coefficients in the balanced equation, convert moles Ca(NO3)2 to moles Li.

4. Convert moles Li to grams Li. grams = moles Li x atomic mass Li.

5. Go back to step 3 and convert to each product in the equation, then convert those moles to grams.

Post your work if you get stuck.