Posted by **Matthew** on Monday, February 15, 2010 at 3:04pm.

A 500 g piece of metal at 60 degrees celsius is placed in 200g of water at 22 degrees celsius contained in a coffee cup calorimeter. The metal and water come to the same temperature at 32.5 degrees cesius. The specific heat of the water is 4.184 j/g(degrees celsius)

a) how much heat energy did the metal give up to the water?

b) what is the specific heat capacity of the metal?

THANKS SOO MUCH~~~

- AP Chemistry -
**DrBob222**, Monday, February 15, 2010 at 3:58pm
[mass metal x specific heat metal x (Tfinal-Tinitial)] +[(mass water x specific heat water x (Tfinal-Tinitial)] = 0

Solve for specific heat metal, the only unknown in the equation.

The first set of brackets is the loss of heat from the metal, the second set of brackets is the gain of heat by water.

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