posted by Andrew on .
The combustion of 1.00 mol of sucrose,C12H22,O11, evolves 5650 kJ of heat. A bomb calorimeter has a calibrated heat capacity of 1.23 kj/degree Celsius. How many grams of sucrose should be burned to raise the temperature of the calorimeter and its contents from 23 degrees C to 80 degrees C?
How much heat is need to raise the T of the calorimeter and its contents from 23 to 80 C?
1.23 kJ/oC x (80-23) = 70.11 kJ.
So burning 1 mole sucrose (342 grams is it--check me out on that) produces 5650 kJ.
342 g x (70.11/5650) = ?? g sucrose. Check my thinking.