Posted by mike on Sunday, February 14, 2010 at 10:07pm.
101 km/h = 28.06 m/s
To decelerate from velocity V in a distance X at a rate of a = 300 m/s^2,
V = sqrt(2 a X)
X = V^2/(2 a) = 1.3 meters
This assumes the crash is into an immovable object, so that all deceleration is achieved by collapsing the front end. A collision with another car or a soft barrier might have a different result. This is a good approximation for a head-on collision with a similar car.
i want to ask you a question
how do i do this problem
The Math Behind the Law How much force is Mike applying to the 1000 kg car to make it accelerate at a rate of .05 m/s2?
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