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April 17, 2014

April 17, 2014

Posted by **mike** on Sunday, February 14, 2010 at 10:07pm.

Thanks.

- 8th grade science -
**drwls**, Monday, February 15, 2010 at 7:30am101 km/h = 28.06 m/s

To decelerate from velocity V in a distance X at a rate of a = 300 m/s^2,

V = sqrt(2 a X)

X = V^2/(2 a) = 1.3 meters

This assumes the crash is into an immovable object, so that all deceleration is achieved by collapsing the front end. A collision with another car or a soft barrier might have a different result. This is a good approximation for a head-on collision with a similar car.

- 8th grade science -
**nene**, Monday, February 22, 2010 at 7:19pmi want to ask you a question

- 8th grade science -
**shellie**, Friday, March 5, 2010 at 2:45pmhow do i do this problem

The Math Behind the Law How much force is Mike applying to the 1000 kg car to make it accelerate at a rate of .05 m/s2?

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