Calculate the volume (L) of the solute C4H8O and the volume (mL) of the solvent C2H5OH that should be combined to prepare 5.54 kg of a solution that is 0.608 m.


Molar Mass (g/mol)
C4H8O 72.12
C2H5OH 46.07

Density (kg/L):
C4H8O 0.8892
C2H5OH 0.7893

Name/Formula:
tetrahydrofuran
C4H8O
ethanol
C2H5OH

0.608 m WHAT?

m means molality

To calculate the volume of the solute (C4H8O) and the volume of the solvent (C2H5OH) needed to prepare a solution, we can use the equation:

Molarity (M) = moles of solute / volume of solution (in liters).

First, we need to calculate the number of moles of the solute C4H8O. We can use the equation:

moles = mass / molar mass.

Given that the mass of the solution is 5.54 kg and the molar mass of C4H8O is 72.12 g/mol, we convert the mass to grams:

mass = 5.54 kg × 1000 g/kg = 5540 g.

Now we can calculate the number of moles:

moles of C4H8O = 5540 g / 72.12 g/mol = 76.81 mol.

Next, we need to calculate the volume of the solution. We can rearrange the equation for molarity:

volume of solution = moles of solute / molarity.

Given that the molarity (M) is 0.608 m and the moles of C4H8O is 76.81 mol, we can calculate the volume of the solution:

volume of solution = 76.81 mol / 0.608 mol/L ≈ 126.37 L.

Since the molarity is the ratio of moles of solute to the volume of solution in liters, we can divide the volume of C4H8O and C2H5OH by the molarity to obtain the individual volumes.

volume of C4H8O = 126.37 L × 0.608 m = 76.86 L.

volume of C2H5OH = 126.37 L × 0.392 m = 49.51 L.

Finally, we need to convert the volumes from liters to milliliters:

volume of C4H8O = 76.86 L × 1000 mL/L = 76,860 mL.

volume of C2H5OH = 49.51 L × 1000 mL/L = 49,510 mL.

Therefore, you would need to combine approximately 76,860 mL of C4H8O and 49,510 mL of C2H5OH to prepare a solution of the desired concentration.