Algebra II
posted by Courtney .
V(X)=x^35x^28x+12
the depth is x+2
Find linear expressions with integer coefficients for the other dimensions and next if the depth of the chest is 9feet deep what are the other dimensions?

V = depth * width * length
V = (x+2) * w * l = x^3  5x^2 8x +12
so divide x^3  5x^2 8x +12 by (x+2)
and get
l * b = x^2 7x +6
which is
(x6)(x1)
so
length = x1
width = x6
depth = x+2
take it from there