Posted by Fabian on Sunday, February 14, 2010 at 1:51pm.
The height of each is
h1=78+(-5)t-4.9t^2
h2=0+50t-4.9t^2
set them equal, solve for t.
Then put time t into either, to solve for final height.
The acceleration due to gravity on planet X is
one fifth that on the surface of the earth.
If it takes 3.9 s for an object to fall a certain
distance from rest on earth, how long would
it take to fall the same distance on planet X?
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