I got all but this problem, I

A 0.145-kg baseball is pitched at 42.0 m/s. The batter hits it horizontally to the pitcher at 58 m/s.

A. Find change in momentum? Is it =.145*58-(-.145*42)=1.45-kg m/s?

B. If bat and ball are in contact for 4.6 x 10-4 s, what is average force during contact?

A. To find the change in momentum, we use the formula:

Change in momentum = m(vf - vi)

where m is the mass of the baseball, vf is the final velocity, and vi is the initial velocity.

Change in momentum = 0.145 kg * (58 m/s - (-42 m/s))

Change in momentum = 0.145 kg * (100 m/s)

Change in momentum = 14.5 kg*m/s

B. To find the average force during contact, we use the formula:

Average force = (change in momentum) / (time in contact)

Average force = (14.5 kg*m/s) / (4.6 x 10^-4 s)

Average force = 31521.74 N

So, the average force during contact is approximately 31,522 N.

To find the change in momentum, you can use the following formula:

Change in momentum = final momentum - initial momentum

A. First, let's find the initial momentum of the baseball. The initial momentum is the product of the mass and the initial velocity:

Initial momentum = mass * initial velocity
Initial momentum = 0.145 kg * 42.0 m/s

Next, let's find the final momentum of the baseball. The final momentum is the product of the mass and the final velocity:

Final momentum = mass * final velocity
Final momentum = 0.145 kg * 58 m/s

Now we can calculate the change in momentum:

Change in momentum = Final momentum - Initial momentum
Change in momentum = (0.145 kg * 58 m/s) - (0.145 kg * 42.0 m/s)

Calculating that, we get:

Change in momentum = 8.41 kg m/s

So the change in momentum is 8.41 kg m/s.

B. To find the average force during contact, we can use the following formula:

Average force = Change in momentum / Time

In this case, the change in momentum is 8.41 kg m/s, as we found in part A. The time of contact is given as 4.6 x 10^(-4) s.

Plugging these values into the formula, we get:

Average force = 8.41 kg m/s / (4.6 x 10^(-4) s)

To simplify, we can write the time in scientific notation as well:

Average force = 8.41 kg m/s / 4.6 x 10^(-4) s

Now we can simplify:

Average force = 18304.35 N

Therefore, the average force during contact is approximately 18304.35 N.

A. To find the change in momentum, we need to calculate the initial momentum and the final momentum, and then subtract the initial momentum from the final momentum.

Initial momentum = mass x initial velocity = 0.145 kg x 58 m/s = 8.41 kg·m/s
Final momentum = mass x final velocity = 0.145 kg x (-42 m/s) = -6.09 kg·m/s

Change in momentum = Final momentum - Initial momentum
= -6.09 kg·m/s - 8.41 kg·m/s
= -14.50 kg·m/s

So, the change in momentum is -14.50 kg·m/s.

B. To find the average force during contact, we can use the equation:

Average Force = Change in momentum / Time

Given that the change in momentum is -14.50 kg·m/s and the time is 4.6 x 10^-4 s, we can calculate the average force.

Average Force = -14.50 kg·m/s / (4.6 x 10^-4 s)
= -31,521.74 N

So, the average force during contact is approximately -31,521.74 N.