Given:
3H2(g) + N2(g) 2NH3(g)
If the reaction starts with 0.500 mol of H2, how many atoms of hydrogen in the compound NH3 would you expect to make?
1. You don't have an arrow but I assume it goes between N2 and 2NH3.
2. You have no Kp or Kc listed.
3. You won't make any hydrogen atoms. Perhaps you meant, "How many atoms of hydrogen will be in the NH3 formed."
To determine the number of atoms of hydrogen in the compound NH3, we can use stoichiometry.
From the balanced chemical equation: 3H2(g) + N2(g) → 2NH3(g), we can see that it takes 3 moles of H2 to produce 2 moles of NH3.
Therefore, the molar ratio of H2 to NH3 is 3:2.
Since we have 0.500 mol of H2, we can calculate the number of moles of NH3 produced:
0.500 mol H2 × (2 mol NH3 / 3 mol H2) = 0.333 mol NH3
Now, we can use Avogadro's number, which states that there are 6.022 x 10^23 atoms in one mole of a substance, to convert moles of NH3 to atoms of hydrogen:
0.333 mol NH3 × (6.022 x 10^23 atoms / 1 mol NH3) = 2.007 x 10^23 atoms of hydrogen
Therefore, if the reaction starts with 0.500 mol of H2, we would expect to produce approximately 2.007 x 10^23 atoms of hydrogen in the compound NH3.
To find the number of hydrogen atoms in the compound NH3, we can use stoichiometry. The balanced equation tells us that 3 moles of H2 reacts with 2 moles of NH3.
First, let's convert the given 0.500 mol of H2 to moles of NH3:
0.500 mol H2 * (2 mol NH3 / 3 mol H2) = 0.333 mol NH3
Now we can use Avogadro's number to convert the moles of NH3 to the number of hydrogen atoms:
0.333 mol NH3 * (6.02 x 10^23 atoms/mol) = 2 x 10^23 hydrogen atoms
Therefore, you would expect to make 2 x 10^23 hydrogen atoms in the compound NH3.