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March 26, 2015

March 26, 2015

Posted by **Heather** on Saturday, February 13, 2010 at 2:30pm.

- Math -
**drwls**, Saturday, February 13, 2010 at 2:59pmSet this up as an algebra problem in two variables. Let X be borrowed at 10% and Y be borrowed at 8%. Here is what you know:

X + Y = 16,000

0.10X + 0.08Y = 1390

Solve by substitution, or by multiplying the second equation by 10 and subtracting from the first.

X + 0.8Y = 13900

0.2Y = 2100

Y = 10,500

Now solve for X. It is the rest of the $16,000.

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