Posted by **ucieng** on Saturday, February 13, 2010 at 2:09pm.

The vector position of a 3.80 g particle moving in the xy plane varies in time according to the following equation.

r1=(3i+3j)t+2jt^2

At the same time, the vector position of a 5.35 g particle varies according to the following equation.

r2=3i-2it^2-6jt

For each equation, t is in s and r is in cm. Solve the following when t = 2.60

Find the vector position of the center of mass.(i+j)

## Answer This Question

## Related Questions

- Physics - The vector position of a 3.80 g particle moving in the xy plane varies...
- Physics - The vector position of a 3.00 g particle moving in the xy plane varies...
- PHysics - The vector position of a 3.65 g particle moving in the xy plane varies...
- Physics - The vector position of a 3.40 g particle moving in the xy plane ...
- Physics - The vector position of a 3.45 g particle moving in the xy plane ...
- Physics - The vector position of a 3.45 g particle moving in the xy plane ...
- Physics - The vector position of a 3.45 g particle moving in the xy plane ...
- Physics - The vector position of a 3.45 g particle moving in the xy plane ...
- physics - The vector position of a 3.75 g particle moving in the xy plane ...
- physics - The acceleration of a particle moving only on a horizontal plane is ...

More Related Questions