Posted by **Anonymous** on Saturday, February 13, 2010 at 12:22pm.

determine the slope of the tangent for the following function. Then determine the equation of the tangent line at x=1

F(x) = x

F(x) = x^4

- calculus -
**Anonymous**, Saturday, February 13, 2010 at 1:07pm
For F(x) = x, the first derivative - which is the slope of the line tangent to a curve - would be:

F'(x) = 1

For the second part, it doesn't matter what value x is, F'(x) is always 1.

For F(x) = x^4, the first derivative - which is the slope of the line tangent to a curve - would be:

F'(x) = 3x^3

For the second part, you just plug in 1 for x:

F'(x) = 3(1)^3 = 3

- calculus -
**Anonymous**, Saturday, February 13, 2010 at 3:45pm
HOLD ON!!! MY BAD!

The second function's derivative is wrong. Brain fart on my part.

For F(x) = x^4, the first derivative - which is the slope of the line tangent to a curve - would be:

F'(x) = 4x^3

For the second part of the question, you just plug in 1 for x:

F'(x) = 4(1)^3 = 4

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