Posted by Anonymous on Saturday, February 13, 2010 at 12:22pm.
determine the slope of the tangent for the following function. Then determine the equation of the tangent line at x=1
F(x) = x
F(x) = x^4

calculus  Anonymous, Saturday, February 13, 2010 at 1:07pm
For F(x) = x, the first derivative  which is the slope of the line tangent to a curve  would be:
F'(x) = 1
For the second part, it doesn't matter what value x is, F'(x) is always 1.
For F(x) = x^4, the first derivative  which is the slope of the line tangent to a curve  would be:
F'(x) = 3x^3
For the second part, you just plug in 1 for x:
F'(x) = 3(1)^3 = 3

calculus  Anonymous, Saturday, February 13, 2010 at 3:45pm
HOLD ON!!! MY BAD!
The second function's derivative is wrong. Brain fart on my part.
For F(x) = x^4, the first derivative  which is the slope of the line tangent to a curve  would be:
F'(x) = 4x^3
For the second part of the question, you just plug in 1 for x:
F'(x) = 4(1)^3 = 4
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