Tuesday

September 16, 2014

September 16, 2014

Posted by **ucieng** on Friday, February 12, 2010 at 10:51pm.

r1=(3i+3j)t+2jt^2

At the same time, the vector position of a 5.35 g particle varies according to the following equation.

r2=3i-2it^2-6jt

For each equation, t is in s and r is in cm. Solve the following when t = 2.60

(a) Find the vector position of the center of mass.(i+j)

- Physics -
**drwls**, Saturday, February 13, 2010 at 3:15pmUse your equations to get the vector locations of each particle at t = 2.60.

Call then (X1,Y1) and (X2,Y2) (or X1i + XY1j and X2i + Y2j))

The X and Y coordinates of the CM will be the mass-weighted mean location:

Xcm = (M1 X1 + M2 X2)/(M1 + M2)

etc.

**Answer this Question**

**Related Questions**

physics - The vector position of a 3.80 g particle moving in the xy plane varies...

Physics - The vector position of a 3.00 g particle moving in the xy plane varies...

PHysics - The vector position of a 3.65 g particle moving in the xy plane varies...

Physics - The vector position of a 3.45 g particle moving in the xy plane ...

Physics - The vector position of a 3.45 g particle moving in the xy plane ...

Physics - The vector position of a 3.45 g particle moving in the xy plane ...

Physics - The vector position of a 3.45 g particle moving in the xy plane ...

Physics - The vector position of a 3.40 g particle moving in the xy plane ...

physics - The vector position of a 3.75 g particle moving in the xy plane ...

physics - The acceleration of a particle moving only on a horizontal plane is ...