how can you arrange these bonds from most polar to least polar
O-C
N-N
N-O
See my answer here.
http://www.jiskha.com/display.cgi?id=1266031249
To arrange the bonds from most polar to least polar, we need to consider the electronegativity difference between the atoms involved in each bond. Electronegativity is a measure of an atom's ability to attract electrons towards itself in a chemical bond.
The greater the difference in electronegativity between two atoms, the more polar the bond will be. In general, oxygen (O) and nitrogen (N) atoms are more electronegative than carbon (C) atoms.
Let's compare each pair of atoms to determine the electronegativity difference and thus the polarity of each bond:
1. N-O:
Nitrogen has an electronegativity value of 3.04, while oxygen has an electronegativity value of 3.44. The electronegativity difference is 0.4.
2. O-C:
Oxygen has an electronegativity value of 3.44, while carbon has an electronegativity value of 2.55. The electronegativity difference is 0.89.
3. N-N:
Both nitrogen atoms have an electronegativity value of 3.04 since they are the same element. The electronegativity difference is 0.
Now, let's arrange the bonds from most polar to least polar based on their electronegativity differences:
1. O-C (0.89)
2. N-O (0.4)
3. N-N (0)
Therefore, the bonds arranged from most polar to least polar are O-C, N-O, and N-N.