Saturday

August 30, 2014

August 30, 2014

Posted by **Sarah Mae B. Oquindo** on Friday, February 12, 2010 at 10:10am.

Investment. Part of $25,000 is invested at 10 percent, another part is invested at 12 percent, and a third part is invested at 16 percent. The total yearly income from these three investments is $3,200. Furthermore, the income from the 16 percent investment yields the same amount as the sum of the incomes from the other two investments. How much is invested at each rate?

- algebra -
**bobpursley**, Friday, February 12, 2010 at 12:09pmLet A, B, C be the amounts invested at 10, 12, and 16 percent.

A*.10+B*.12+C*.16=3200

C*.16=A*.10+B*.12

A+B+C=25,000

Can you solve it now?

**Related Questions**

math - 1. Investment. Part of $25,000 is invested at 10 percent, another part is...

algebra - two investments were made totaling $15,000. for a certain year these ...

algebra - Janet invested $23,000, part at 6% and part at 17%. If the total ...

Math Help Please - Bob invested $30,000, part at 10% and part at 1%. If the ...

Math - A total of $11,000 was invested. Part of the $11,000 was invested at 4% ...

MATHH - Suppose 10,000 is invested at 6 percent.how much additional money must ...

math - A person has invested $6000 . Part of the money is invested at 3% and ...

Algebra - A man invested $15,000. Part of the investment was put into an account...

Algebra - $9500 is invested part of it at 12% and part of it at 7%. For a ...

iun - kim won 60,000 dollars. she invested part at 2 percent interest and the ...