Posted by Sarah Mae B. Oquindo on Friday, February 12, 2010 at 10:10am.
Let A, B, C be the amounts invested at 10, 12, and 16 percent.
A*.10+B*.12+C*.16=3200
C*.16=A*.10+B*.12
A+B+C=25,000
Can you solve it now?
Related Questions
math - 1. Investment. Part of $25,000 is invested at 10 percent, another part is...
algebra - two investments were made totaling $15,000. for a certain year these ...
Math Help Please - Bob invested $30,000, part at 10% and part at 1%. If the ...
math - please explain: sam invested part of his $25,000 bonus in a fund that ...
algebra - Janet invested $23,000, part at 6% and part at 17%. If the total ...
Math - A total of $11,000 was invested. Part of the $11,000 was invested at 4% ...
math - A person has invested $6000 . Part of the money is invested at 3% and ...
Math - An investment advisor invested a total of $12,000, part at 2.5% annual ...
algebra - $6300 is invested,part of it at 10% and part of it at 7%.For a certain...
algebra - $6300 is invested,part of it at 10% and part of it at 7%.For a certain...
For Further Reading