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1. Investment. Part of $25,000 is invested at 10 percent, another part is invested at 12 percent, and a third part is invested at 16 percent. The total yearly income from these three investments is $3,200. Furthermore, the income from the 16 percent investment yields the same amount as the sum of the incomes from the other two investments. How much is invested at each rate?

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    Suppose x is invested at 10%, y is invested at 12% and z is invested at 16%. Here is what you know:
    x + y + z = 25,000
    0.10 x + 0.12 y + 0.16 z = 3200
    0.16 z = 0.10 x + 0.12 y

    You can immediatley write
    2*(0.16 z) = 0.32z = 3200
    So z = $10,000

    Therefere x + y = $15,000.
    You also know that
    0.10x + 0.12 y = 1600

    Now finish it. You have two equations in two unknowns left.

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