Posted by **val** on Thursday, February 11, 2010 at 11:17pm.

the length of a rectangular garden is 5 feet longer than its width. The garden is surrounded by a 2-foot-wide-sidewalk. The sidewalk has an area of 76 square feet. Find the dimensions of the garden

- 8th grade algebra -
**Reiny**, Thursday, February 11, 2010 at 11:55pm
Let the width of the garden be x ft

then the length is x+5 ft.

area = x(x+5)

width of garden with sidewalk = x+4

length of garden with sidewalk = x+9

(x+4)(x+9) - x(x+5) = 76

solve, the x^2 will drop out

- 8th grade algebra -
**Safia**, Sunday, October 27, 2013 at 3:02pm
(X+4)(x+9)-x(x+5)=76

(x^2+9x+4x+36)-x(x+5)=76

x^2+13x+36-x^2-5x=76

X^2 will drop and we will combine the like terms(13x and -5x) and 36 will go to the other side

8x=76-36

8x=40

x=5

W=5ft

L=10ft since L=x+5

- 8th grade algebra -
**anna**, Tuesday, February 23, 2016 at 8:58pm
Area of living room with length being X+5 and width being 20

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