Physics
posted by Anonymous on .
In one of the original Doppler experiments, one tuba was played on a moving platform car at a frequency of 75 Hz, and a second identical one was played on the same tone while at rest in the railway station. What beat frequency was heard if the train approached the station at a speed of 18.0 m/s?

calculate the doppler frequency , then the difference in that and 75 is the beat.

that answer is not helpful enough to someone who is struggling with the material.
f'=f(v)/(vvs)=75(340)/(34018)=DO MATH
fbeat=f'f
so sub f from calculated #