Post a New Question
posted by <3 on Thursday, February 11, 2010 at 4:15pm.
Evaluate the definite integral. xe^(–x^2)dx from 0 to 6
dx x e^-x^2 well d/dx (e^-x^2) = -2 x e^-x^2 so I will guess (-1/2) e^-x^2 from 0 to 6 (-1/2) e^-36 - (-1/2)e^0 looks like about 1/2
More Related Questions