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Calculus

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Evaluate the definite integral.
xe^(–x^2)dx from 0 to 6

  • Calculus - ,

    dx x e^-x^2

    well d/dx (e^-x^2) = -2 x e^-x^2

    so I will guess

    (-1/2) e^-x^2 from 0 to 6

    (-1/2) e^-36 - (-1/2)e^0

    looks like about 1/2

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