Wednesday

March 4, 2015

March 4, 2015

Posted by **Max** on Thursday, February 11, 2010 at 4:06pm.

- Physics -
**bobpursley**, Thursday, February 11, 2010 at 4:09pmYou are answer grazing, I think.

What is your thinking on this?

- Physics -
**Max**, Thursday, February 11, 2010 at 4:21pmI am not answer grazing. I just don't know how to do these couple problems at all. I have no idea where to start.

- Physics -
**bobpursley**, Thursday, February 11, 2010 at 4:54pmLet Vi be the velocity. The vertical component then is Vi sin24. The horizontal component is Vi Cos24

In the horizontal, you know distance, time, solve for Vi.

Then, knowing Vi, you know the vi vertical, time in air. Solve for hi

hf=hi+vivertical*t-4.9 t^2

Finally, max height occurs when vivertical is zero. Find that time, then find h.

- Physics -
**Max**, Thursday, February 11, 2010 at 6:45pmWhat is the equation you use, knowing distance and time, to get Vi?

- Physics -
**Max**, Thursday, February 11, 2010 at 7:03pmOk I figured out Vi. Now I don't get what you put in for Hf because you can't have two variables to find out Hi?

- Physics -
**Max**, Thursday, February 11, 2010 at 7:38pmI'm still not able to find Hi with the given equation. Could you possibly explain more on how to get the initial height?

- Physics -
**Damon**, Thursday, February 11, 2010 at 7:55pmFrom the edge of the rooftop of a building, a boy throws a stone at an angle 24.0° above the horizontal. The stone hits the ground 4.40 s later, 104 m away from the base of the building. (Ignore air resistance.) Find the initial velocity of the stone and magnitude and direction above the horizontal. Find the initial height h from which the stone was thrown. Find the maximum height H reached by the stone.

a = -9.8

U = Speed cos 24 = S cos 24

Vi = Speed sin 24 = S sin 24

V = Vi - 9.8 t

h = Hi + Vi t - 4.9 t^2

First find the constant horizontal speed U = 104/4.4

then the initial speed S = (104/4.4)/cos 24

then the initial velocity up Vi = S sin 24

h = 0 at ground so

0 = H +Vi t -4.9 t^2

but t = 4.4 so solve for H

also

at the top, v = 0

so

0 = Vi - 9.8 t at top

that gives you t at top

use that t in

h = H + Vi t -4.9 t^2

**Answer this Question**

**Related Questions**

Physics - From the edge of the rooftop of a building, a boy throws a stone at an...

Physics - From the edge of the rooftop of a building, a boy throws a stone at an...

physics - From the edge of the rooftop of a building, a boy throws a stone at an...

physics - From the edge of the rooftop of a building, a boy throws a stone at an...

physics - A boy drops a stone-A, down from a cliff 480 meters high, next he ...

physics - a man stand on the top of the building 490 m above the ground.he ...

physics - Multiple part question….. A student stands at the edge of a cliff and ...

physics - A boy standing on top of a hill throws a stone horizontally. The stone...

Physics - A boy is whirling around a stone tied at the end of a 0.71 m long ...

calculus - A stone is thrown straight down from the edge of a roof, 750 feet ...