solve the system by the substitution method x=8-4y
3x=5y=3
Is your subject REALLY college? Are you sure it isn't math?
Your second equation has too many = signs. One of them must be a + or -.
The grade level of this question should not be described as "college"
To solve the system of equations using the substitution method, we'll substitute the value of x from the first equation into the second equation.
Given:
1) x = 8 - 4y
2) 3x + 5y = 3
We'll start by substituting x = 8 - 4y into the second equation:
3(8 - 4y) + 5y = 3
Now, we'll simplify the equation:
24 - 12y + 5y = 3
Combine like terms:
24 - 7y = 3
Next, we want to isolate y. Let's move 24 to the other side by subtracting 24 from both sides:
-7y = 3 - 24
-7y = -21
Finally, divide both sides by -7 to solve for y:
y = (-21) / (-7)
y = 3
Now that we have the value of y, we can substitute it back into the first equation, x = 8 - 4y, to find the value of x:
x = 8 - 4(3)
x = 8 - 12
x = -4
Therefore, the solution to the system of equations is x = -4 and y = 3.