Homework Help: physics

Posted by Sandhya on Thursday, February 11, 2010 at 8:41am.

A particle of charge Q is fixed at the origin of an xy coordinate system. At t = 0 a particle (m = 0.690 g, q = 4.75 湣) is located on the x axis at x = 20.0 cm, moving with a speed of 50.0 m/s in the positive y direction. For what value of Q will the moving particle execute circular motion? (Neglect the gravitational force on the particle

physics - drwls, Thursday, February 11, 2010 at 8:47am
R = 0.30 m and V = 50 m/s.

If V^2/R = k Q q/R^2 , there will be circular motion.

Solve for Q
physics - Sandhya, Thursday, February 11, 2010 at 8:12pm
Here R = 0.20 m

mV^2 /R = kQq/R^2

Am I right?

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