Thursday

September 18, 2014

September 18, 2014

Posted by **Ren** on Thursday, February 11, 2010 at 8:23am.

- arithmetic -
**Reiny**, Thursday, February 11, 2010 at 8:30amThe first, second, and seventh terms of your AP would be

a, a+2, and a+12

but these are supposed to be the first 3 terms of a GP, so

(x+2)/a = (a+12)/(a+2)

cross-multiply, the a^2 drops out and you get

a = 1/2

now you know your first 3 terms of the GP to be

1/2, 5/2, and 25/2

check for common ratio:

(5/2) ÷ (1/2) = 5

(25/2) ÷ (5/2) = 5

- Correction - Typo in arithmetic -
**Reiny**, Thursday, February 11, 2010 at 8:31am(x+2)/a = (a+12)/(a+2)

obviously should have been

(a+2)/a = (a+12)/(a+2)

- arithmetic -
**Ren**, Thursday, February 11, 2010 at 9:13amHey thanks a lot Reiny. I got it..

**Answer this Question**

**Related Questions**

arithmetic - 1. The first and last term of an A.P are, a and l respectively, ...

arithmetic - 1. The first and last term of an A.P are, a and l respectively, ...

Math(arithmetic & Geometric Series) - 1)The sum of 6 terms of an arithmetic ...

Can someone help me?! - The 1st, 5th and 13th terms of an arithmetic sequence ...

Math - The first three terms of a GP are also the first,nineth and eleventh ...

arithmetic - Two arithmetic progression have thd same first and last terms.the ...

Maths - 1..The first 2 terms of a geometric progression are the same as the ...

arithmetic - I have a Q that im trying to solve: it says: the 1st , 2nd, and 3rd...

Algebra - Determine whether each sequence is arithmetic or geometric. Find the ...

math - Determine whether each sequence is arithmetic or geometric. Find the next...