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December 20, 2014

December 20, 2014

Posted by **ashley** on Wednesday, February 10, 2010 at 10:32pm.

- statistics -
**PsyDAG**, Thursday, February 11, 2010 at 11:48amWhat is the variability of this count? More information needed.

- statistics -
**John**, Wednesday, February 17, 2010 at 4:29amI've been working this out and can't get the answer shown in the book...I use mu = 1/4 thus lambda = 4 P(X > 2) = 1-(1-F(x)) = e^-4x = e^-8 This is not the answe given however so I am lost on this one.

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