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a person standing at the edge of a seaside cliff kicks a stone over the edge with a speed of 18 m/s. the cliff is 52 m above the waters surface. how long does it take for the stone to fall to the water? with what speed does it strike the water.

vi= +18 m/s

h= 52m

* theres an arrow for g pointing down.

  • physics -

    The time to fall (t) can be computed using
    (1/2) g t^2 = 52 m

    The final speed can be calculated by realizing that the kinetic energy increases by M g H. That means that
    V^2 increases by 2 g H.
    Vfinal^2 = 18^2 + 2*9.8*52

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