Two cards are chosen at random from a standard deck of cards with replacement. What is the probability of getting 2 aces?
Is is an independent events? If it is then would it be 2/52(chances of an ace) x 2/52?
Math - Reiny, Wednesday, February 10, 2010 at 10:19pm
since you are replacing it, the second event is not affected by the result of the first event, so the events are independent.
Prob = 4/52 x 4/52
(why do you have 2/52 ? Aren't there 4 aces?)
Math - Shadow, Wednesday, February 10, 2010 at 10:34pm
I confused the PROBABILITY OF GETTING 2 ACES. Thank you very much.
Could you review this one too please.
A jar hold 15 red pencils and 10 blues pencils. What is the probability of drawing two red pencil form the jar?
This would be an dependent and it would be 15/25( first time) x 14/24(second time)?
Math - Reiny, Wednesday, February 10, 2010 at 10:37pm
correct! reduce it to 7/20
Math - Shadow, Wednesday, February 10, 2010 at 10:40pm
Thanks for the help, Reiny.
Math - Ariel, Wednesday, April 4, 2012 at 11:15pm
That is very correct 7/20 I've been a math teacher for over 30 years. And I had my students do 9-7 Independent And Dependent Events And we did 1-9 togather. So then I said 10 is a hard one i'm gone let them sweat. I know why you get 15/25 because 15 red pencils and add 15+10=25 so then that's 15/25 * 14/24 = 7/20 . Have a nice day. But it's not cool to get answers off the internet your math teacher will think you really really tried. But okay.