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January 31, 2015

January 31, 2015

Posted by **Shadow** on Wednesday, February 10, 2010 at 9:07pm.

1.P(black,queen)

2.P(jack,queen)

How would I solve these type of problems?

- Math -
**Damon**, Wednesday, February 10, 2010 at 9:37pmIf you replace the first card and shuffle before drawing the second the two drawings are independent and the chance of black, queen is the product of the queen probability and the black probability.

(4/52)(1/2) which is 2/52

which you could have said immediately because there are 2 black queens in a deck of 52 cards.

- Math -
**Shadow**, Wednesday, February 10, 2010 at 9:40pmMay I ask where did you get 4/52 and 1/2?

- Math -
**Damon**, Thursday, February 11, 2010 at 5:39amFour out of 52 cards are queens.

1/2 of all the cards are black.

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