Posted by **sara** on Wednesday, February 10, 2010 at 5:58pm.

in an isosceles triangle the vertex angle measures 90 degrees and the length of each congruent leg is 5√2. whats the length of the base?

- MATH trigonometry -
**Reiny**, Wednesday, February 10, 2010 at 6:00pm
Isn't the base the hypotenuse of a right-angled triangle?

so h^2 = (5√2)^ + (5√2)^2

= .......

- MATH trigonometry -
**sara**, Wednesday, February 10, 2010 at 6:02pm
20?

- MATH trigonometry -
**Reiny**, Wednesday, February 10, 2010 at 6:10pm
How did you come up with that?

- MATH trigonometry -
**sara**, Wednesday, February 10, 2010 at 6:26pm
i put it into the calculator and i got 20

- MATH trigonometry -
**Reiny**, Wednesday, February 10, 2010 at 6:35pm
You should not need a calculator.

h^2 = (5√2)^ + (5√2)^2

= 50 + 50

= 100

h = √100 = 10

- MATH trigonometry -
**sara**, Wednesday, February 10, 2010 at 6:39pm
oohh okay i get it now

thank you soo muchh!

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