Posted by Joe on Wednesday, February 10, 2010 at 4:39pm.
let the original price be $x
after the first discount of 10%, the cost is (.9)x
after the second discount , the cost is (.9)(.9)x = (.9)^2x
after the third discount, the cost is (.9)^3x
.
.
after the 4th discount the cost is (.9)^5x
so percentage of final price to original price is
(.9)^5x/x = .9^5 = .5905 = appr. 59%
so it was reduced by 41%
Oh thanks!
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