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February 28, 2015

February 28, 2015

Posted by **Joe** on Wednesday, February 10, 2010 at 4:39pm.

I'm not sure where to begin since I don't know what the original price of the lamp was. Can you please get me started?

- Math -
**Reiny**, Wednesday, February 10, 2010 at 5:20pmlet the original price be $x

after the first discount of 10%, the cost is (.9)x

after the second discount , the cost is (.9)(.9)x = (.9)^2x

after the third discount, the cost is (.9)^3x

.

.

after the 4th discount the cost is (.9)^5x

so percentage of final price to original price is

(.9)^5x/x = .9^5 = .5905 = appr. 59%

so it was reduced by 41%

- Math -
**Joe**, Wednesday, February 10, 2010 at 5:23pmOh thanks!

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