Posted by Vinnnie on Wednesday, February 10, 2010 at 11:02am.
Another algebra problem in two variables. Why are you changing names?
Please show your work for further assistance.
I'm not changing names. This is the only one that I posted today. Because this is the only one out of my homework that I don't understand how to do.
Let X = cc of 10% iodine solution
Let Y = cc of 15% iodine solution
X + Y = 20
(0.1X + 0.15 Y) = 0.12*20
X + 1.5 Y = 24
0.5Y = 4
Take it from there.
Thanx :)
Related Questions
Math - How many gallons of 15% iodine solution should be mixed with 40% iodine ...
Math - A chemist working on a flu vaccine needs to mix a 10% sodium-iodine ...
chemistry - When 7.50 grams of iodine (I2) is added to 48.7 grams of carbon ...
Chemistry - A student has 100.0 mL of an unknown solution of Vitamin C. She ...
Chemistry - A student has 100.0 mL of an unknown solution of Vitamin C. She ...
Chemistry - A student has 100.0 mL of an unknown solution of Vitamin C. She ...
math - A chemist has 80 pints of a 20% iodine solution. How many pints of iodine...
Chemistry - A solution of iodine (I2) in carbon tetra-chloride(CCl4) is used ...
Chemistry - when 7.50 grams of iodine (I2) is added to 48.7grams of carbon ...
Chemistry - A solution of I2 was standardized with ascorbic acid. Using a .1000 ...
For Further Reading