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March 29, 2015

March 29, 2015

Posted by **Vinnnie** on Wednesday, February 10, 2010 at 11:02am.

- Math -
**drwls**, Wednesday, February 10, 2010 at 11:12amAnother algebra problem in two variables. Why are you changing names?

Please show your work for further assistance.

- Math -
**Vinnie**, Wednesday, February 10, 2010 at 11:20amI'm not changing names. This is the only one that I posted today. Because this is the only one out of my homework that I don't understand how to do.

- Math -
**drwls**, Wednesday, February 10, 2010 at 3:25pmLet X = cc of 10% iodine solution

Let Y = cc of 15% iodine solution

X + Y = 20

(0.1X + 0.15 Y) = 0.12*20

X + 1.5 Y = 24

0.5Y = 4

Take it from there.

- Math -
**Vinnie**, Wednesday, February 10, 2010 at 3:51pmThanx :)

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