The length of a rectangular swimming pool is 6 feet more than twice its width. Find the length and width of the pool if its perimeter is 84 feet.

I made two mistakes. I was very sloppy reading the problem,. and apologize.

This is how algebra is done. If you don't use this method, you will have to keep trying pairs of numbers until you get as pair that works,

L = 2W + 6 since the length L is 6 more than twice the width, W.

2(L + W) = 84 since that is the perimeter

2L - 4W = 12
2L + 2W = 84
6W = 72
W = 12
L = 30

Thank you for your help!!

To find the length and width of the pool, we can set up an equation based on the given information.

Let's represent the width of the pool as "w" feet.

According to the problem, the length of the pool is 6 feet more than twice its width. So, the length can be represented as "2w + 6" feet.

The perimeter of a rectangle is given by the formula: P = 2(length + width)

Substituting the values, we have:

84 = 2((2w + 6) + w)

Let's simplify this equation to solve for "w":

84 = 2(3w + 6)

Divide both sides of the equation by 2:

42 = 3w + 6

Subtract 6 from both sides:

36 = 3w

Now, divide both sides by 3:

w = 12

Therefore, the width of the pool is 12 feet.

To find the length, substitute the value of "w" back into our expression:

Length = 2w + 6 = 2(12) + 6 = 24 + 6 = 30

So, the length of the pool is 30 feet.

Therefore, the length of the pool is 30 feet and the width of the pool is 12 feet.

Set up the two equations in the two vzriables, length (L) and width (W).

They are:
L - W = 6
and
L W = 84

Then solve them, using algebra.

What do you mean by solving them by using algebra? I don't understand what to do