posted by Macey on .
A sloution of calcium nitrate, C(NO3), reacts with a solution of ammonium fluoride, NH4F, to form solid calcium fluoride, CaF2, and ammonium nitrate, NH4NO3(ag). When 45.00 mL of 4.8724 x 10 -1M Ca(NO3)2 solution was added to 60.00 mL of 9.9981 x 10 -1M NH4F solution, 1.524g of CaF2 was isolated.
(1) Write the equation for the reaction, showing the staes of substances.
(2) Calculate the number of moles of Ca(NO3)2 orginally present.
(3) calculate the number of moles of NH4F present
(4) Identify the limiting reagent.
(5) Calculate the theoretical yeild, in grams, of CaF2.
(6) Calculate the percent yield of CaF2.